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12x+7x^2=12
We move all terms to the left:
12x+7x^2-(12)=0
a = 7; b = 12; c = -12;
Δ = b2-4ac
Δ = 122-4·7·(-12)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{30}}{2*7}=\frac{-12-4\sqrt{30}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{30}}{2*7}=\frac{-12+4\sqrt{30}}{14} $
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